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13004256351673 is a prime number
BaseRepresentation
bin1011110100111100101000…
…0101001001010110111001
31201001012020222120121010001
42331033022011021112321
53201030204111223143
643354023424553001
72511345411113056
oct275171205112671
951035228517101
1013004256351673
11416408a765804
12156038b182761
137343b07345c2
1432d5a342a02d
1517840d19814d
hexbd3ca1495b9

13004256351673 has 2 divisors, whose sum is σ = 13004256351674. Its totient is φ = 13004256351672.

The previous prime is 13004256351659. The next prime is 13004256351739. The reversal of 13004256351673 is 37615365240031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12519517353849 + 484738997824 = 3538293^2 + 696232^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13004256351673 is a prime.

It is a super-2 number, since 2×130042563516732 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13004256351773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502128175836 + 6502128175837.

It is an arithmetic number, because the mean of its divisors is an integer number (6502128175837).

Almost surely, 213004256351673 is an apocalyptic number.

It is an amenable number.

13004256351673 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004256351673 is an equidigital number, since it uses as much as digits as its factorization.

13004256351673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 46.

The spelling of 13004256351673 in words is "thirteen trillion, four billion, two hundred fifty-six million, three hundred fifty-one thousand, six hundred seventy-three".