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130043022244334 = 2167389350366001
BaseRepresentation
bin11101100100011000000000…
…001001010111100111101110
3122001102222202210221202002122
4131210120000021113213232
5114021111102143304314
61140324534545552542
736251204214562313
oct3544300011274756
9561388683852078
10130043022244334
1138487a3292a161
1212703261045752
135774009809ab4
142418189cc2d0a
151007ab656a28e
hex7646002579ee

130043022244334 has 8 divisors (see below), whose sum is σ = 196232584465008. Its totient is φ = 64632160756000.

The previous prime is 130043022244273. The next prime is 130043022244357. The reversal of 130043022244334 is 433442220340031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1300430222443342 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130043022244294 and 130043022244303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194675182667 + ... + 194675183334.

It is an arithmetic number, because the mean of its divisors is an integer number (24529073058126).

Almost surely, 2130043022244334 is an apocalyptic number.

130043022244334 is a deficient number, since it is larger than the sum of its proper divisors (66189562220674).

130043022244334 is a wasteful number, since it uses less digits than its factorization.

130043022244334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 389350366170.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 130043022244334 its reverse (433442220340031), we get a palindrome (563485242584365).

The spelling of 130043022244334 in words is "one hundred thirty trillion, forty-three billion, twenty-two million, two hundred forty-four thousand, three hundred thirty-four".

Divisors: 1 2 167 334 389350366001 778700732002 65021511122167 130043022244334