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130043995 = 5174114939
BaseRepresentation
bin1111100000001…
…01000001011011
3100001200220211021
413300011001123
5231242401440
620523143311
73136233004
oct760050133
9301626737
10130043995
1167451a84
1237674b37
1320c32813
14133b21ab
15b63b84a
hex7c0505b

130043995 has 8 divisors (see below), whose sum is σ = 156152880. Its totient is φ = 103968480.

The previous prime is 130043993. The next prime is 130044007. The reversal of 130043995 is 599340031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130043995 - 21 = 130043993 is a prime.

It is a super-2 number, since 2×1300439952 = 33822881271120050, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130043995.

It is not an unprimeable number, because it can be changed into a prime (130043993) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1236 + ... + 16174.

It is an arithmetic number, because the mean of its divisors is an integer number (19519110).

Almost surely, 2130043995 is an apocalyptic number.

130043995 is a deficient number, since it is larger than the sum of its proper divisors (26108885).

130043995 is a wasteful number, since it uses less digits than its factorization.

130043995 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16685.

The product of its (nonzero) digits is 14580, while the sum is 34.

The square root of 130043995 is about 11403.6833961663. The cubic root of 130043995 is about 506.6368415519.

The spelling of 130043995 in words is "one hundred thirty million, forty-three thousand, nine hundred ninety-five".

Divisors: 1 5 1741 8705 14939 74695 26008799 130043995