13004401 has 4 divisors (see below), whose sum is σ = 13020400. Its totient is φ = 12988404.

The previous prime is 13004393. The next prime is 13004449. The reversal of 13004401 is 10440031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13004401 - 2³ = 13004393 is a prime.

It is a super-2 number, since 2×13004401² = 338228890737602, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6711 + ... + 8428.

It is an arithmetic number, because the mean of its divisors is an integer number (3255100).

Almost surely, 2^13004401 is an apocalyptic number.

It is an amenable number.

13004401 is a deficient number, since it is larger than the sum of its proper divisors (15999).

13004401 is an equidigital number, since it uses as much as digits as its factorization.

13004401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15998.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 13004401 is about 3606.1615327104. The cubic root of 13004401 is about 235.1599996860.

Adding to 13004401 its reverse (10440031), we get a palindrome (23444432).

The spelling of 13004401 in words is "thirteen million, four thousand, four hundred one".