1300440241 has 2 divisors, whose sum is σ = 1300440242. Its totient is φ = 1300440240.

The previous prime is 1300440223. The next prime is 1300440247. The reversal of 1300440241 is 1420440031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1135959616 + 164480625 = 33704^2 + 12825^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300440241 - 2⁹ = 1300439729 is a prime.

It is a super-3 number, since 3×1300440241³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1300440247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650220120 + 650220121.

It is an arithmetic number, because the mean of its divisors is an integer number (650220121).

Almost surely, 2^1300440241 is an apocalyptic number.

It is an amenable number.

1300440241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300440241 is an equidigital number, since it uses as much as digits as its factorization.

1300440241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 1300440241 is about 36061.6172820909. The cubic root of 1300440241 is about 1091.5160681040.

Adding to 1300440241 its reverse (1420440031), we get a palindrome (2720880272).

The spelling of 1300440241 in words is "one billion, three hundred million, four hundred forty thousand, two hundred forty-one".