13004404351 has 4 divisors (see below), whose sum is σ = 13005757600. Its totient is φ = 13003051104.

The previous prime is 13004404331. The next prime is 13004404421. The reversal of 13004404351 is 15340440031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15340440031 = 7 ⋅2191491433.

It is a cyclic number.

It is not a de Polignac number, because 13004404351 - 2¹³ = 13004396159 is a prime.

It is a super-2 number, since 2×13004404351² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004404331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 662106 + ... + 681463.

It is an arithmetic number, because the mean of its divisors is an integer number (3251439400).

Almost surely, 2^13004404351 is an apocalyptic number.

13004404351 is a deficient number, since it is larger than the sum of its proper divisors (1353249).

13004404351 is an equidigital number, since it uses as much as digits as its factorization.

13004404351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1353248.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13004404351 its reverse (15340440031), we get a palindrome (28344844382).

The spelling of 13004404351 in words is "thirteen billion, four million, four hundred four thousand, three hundred fifty-one".