Base | Representation |
---|---|
bin | 111100100011100111… |
… | …0111000110110011101 |
3 | 110102122222220222001202 |
4 | 1321013032320312131 |
5 | 4112312242312333 |
6 | 135424052245245 |
7 | 12252420434501 |
oct | 1710716706635 |
9 | 412588828052 |
10 | 130044104093 |
11 | 501735631a2 |
12 | 21253610825 |
13 | c356077427 |
14 | 64192aa301 |
15 | 35b1b765e8 |
hex | 1e473b8d9d |
130044104093 has 2 divisors, whose sum is σ = 130044104094. Its totient is φ = 130044104092.
The previous prime is 130044104011. The next prime is 130044104117. The reversal of 130044104093 is 390401440031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111274282084 + 18769822009 = 333578^2 + 137003^2 .
It is an emirp because it is prime and its reverse (390401440031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130044104093 - 216 = 130044038557 is a prime.
It is a super-2 number, since 2×1300441040932 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130044134093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65022052046 + 65022052047.
It is an arithmetic number, because the mean of its divisors is an integer number (65022052047).
Almost surely, 2130044104093 is an apocalyptic number.
It is an amenable number.
130044104093 is a deficient number, since it is larger than the sum of its proper divisors (1).
130044104093 is an equidigital number, since it uses as much as digits as its factorization.
130044104093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 130044104093 in words is "one hundred thirty billion, forty-four million, one hundred four thousand, ninety-three".
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