Base | Representation |
---|---|
bin | 111100100011100111… |
… | …1000000001010000011 |
3 | 110102122222222111010010 |
4 | 1321013033000022003 |
5 | 4112312244242034 |
6 | 135424053040003 |
7 | 12252420620652 |
oct | 1710717001203 |
9 | 412588874103 |
10 | 130044134019 |
11 | 50173583728 |
12 | 21253626003 |
13 | c356087c37 |
14 | 64192b7199 |
15 | 35b1b803e9 |
hex | 1e473c0283 |
130044134019 has 4 divisors (see below), whose sum is σ = 173392178696. Its totient is φ = 86696089344.
The previous prime is 130044133969. The next prime is 130044134021. The reversal of 130044134019 is 910431440031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130044134019 - 215 = 130044101251 is a prime.
It is a super-2 number, since 2×1300441340192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130044134039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21674022334 + ... + 21674022339.
It is an arithmetic number, because the mean of its divisors is an integer number (43348044674).
Almost surely, 2130044134019 is an apocalyptic number.
130044134019 is a deficient number, since it is larger than the sum of its proper divisors (43348044677).
130044134019 is an equidigital number, since it uses as much as digits as its factorization.
130044134019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43348044676.
The product of its (nonzero) digits is 5184, while the sum is 30.
The spelling of 130044134019 in words is "one hundred thirty billion, forty-four million, one hundred thirty-four thousand, nineteen".
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