13004414401 has 32 divisors (see below), whose sum is σ = 15167088000. Its totient is φ = 11019156480.

The previous prime is 13004414387. The next prime is 13004414419. The reversal of 13004414401 is 10441440031.

It is a cyclic number.

It is not a de Polignac number, because 13004414401 - 2¹⁵ = 13004381633 is a prime.

It is a super-3 number, since 3×13004414401³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004414441) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15686455 + ... + 15687283.

It is an arithmetic number, because the mean of its divisors is an integer number (473971500).

Almost surely, 2^13004414401 is an apocalyptic number.

13004414401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13004414401 is a deficient number, since it is larger than the sum of its proper divisors (2162673599).

13004414401 is a wasteful number, since it uses less digits than its factorization.

13004414401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1569.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 13004414401 its reverse (10441440031), we get a palindrome (23445854432).

The spelling of 13004414401 in words is "thirteen billion, four million, four hundred fourteen thousand, four hundred one".