Base | Representation |
---|---|
bin | 111100100011101000… |
… | …0000100110101100101 |
3 | 110102200000111210000011 |
4 | 1321013100010311211 |
5 | 4112312332242313 |
6 | 135424103050221 |
7 | 12252423202060 |
oct | 1710720046545 |
9 | 412600453004 |
10 | 130044415333 |
11 | 50173756018 |
12 | 21253740971 |
13 | c356155cb1 |
14 | 641934b8d7 |
15 | 35b1bd893d |
hex | 1e47404d65 |
130044415333 has 16 divisors (see below), whose sum is σ = 149909333760. Its totient is φ = 110503483776.
The previous prime is 130044415297. The next prime is 130044415343. The reversal of 130044415333 is 333514440031.
It is not a de Polignac number, because 130044415333 - 221 = 130042318181 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130044415295 and 130044415304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130044415343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 621283 + ... + 803791.
It is an arithmetic number, because the mean of its divisors is an integer number (9369333360).
Almost surely, 2130044415333 is an apocalyptic number.
It is an amenable number.
130044415333 is a deficient number, since it is larger than the sum of its proper divisors (19864918427).
130044415333 is a wasteful number, since it uses less digits than its factorization.
130044415333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183396.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 130044415333 its reverse (333514440031), we get a palindrome (463558855364).
The spelling of 130044415333 in words is "one hundred thirty billion, forty-four million, four hundred fifteen thousand, three hundred thirty-three".
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