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130045155235 = 559943420753
BaseRepresentation
bin111100100011101001…
…0111001011110100011
3110102200001220100221221
41321013102321132203
54112313024431420
6135424130555511
712252432403162
oct1710722713643
9412601810857
10130045155235
1150174110a06
1221253a38b97
13c3563549c8
1464194a13d9
1535b1cd2caa
hex1e474b97a3

130045155235 has 8 divisors (see below), whose sum is σ = 156314714400. Its totient is φ = 103862438784.

The previous prime is 130045155223. The next prime is 130045155239. The reversal of 130045155235 is 532551540031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130045155235 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130045155235.

It is not an unprimeable number, because it can be changed into a prime (130045155239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21707382 + ... + 21713371.

It is an arithmetic number, because the mean of its divisors is an integer number (19539339300).

Almost surely, 2130045155235 is an apocalyptic number.

130045155235 is a deficient number, since it is larger than the sum of its proper divisors (26269559165).

130045155235 is an equidigital number, since it uses as much as digits as its factorization.

130045155235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43421357.

The product of its (nonzero) digits is 45000, while the sum is 34.

Adding to 130045155235 its reverse (532551540031), we get a palindrome (662596695266).

The spelling of 130045155235 in words is "one hundred thirty billion, forty-five million, one hundred fifty-five thousand, two hundred thirty-five".

Divisors: 1 5 599 2995 43420753 217103765 26009031047 130045155235