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13004520222000 = 2435325743319477
BaseRepresentation
bin1011110100111101100111…
…0011101110110100110000
31201001012221101002121011010
42331033121303232310300
53201031224134101000
643354105532350520
72511355064014236
oct275173163566460
951035841077133
1013004520222000
11416420570245a
121560443615440
137344232c23a8
1432d5ca4b6956
1517842641bd50
hexbd3d9ceed30

13004520222000 has 320 divisors, whose sum is σ = 42189082475904. Its totient is φ = 3446223667200.

The previous prime is 13004520221983. The next prime is 13004520222053. The reversal of 13004520222000 is 22202540031.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 667676262 + ... + 667695738.

Almost surely, 213004520222000 is an apocalyptic number.

13004520222000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13004520222000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21094541237952).

13004520222000 is an abundant number, since it is smaller than the sum of its proper divisors (29184562253904).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004520222000 is a wasteful number, since it uses less digits than its factorization.

13004520222000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20193 (or 20177 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 21.

Adding to 13004520222000 its reverse (22202540031), we get a palindrome (13026722762031).

The spelling of 13004520222000 in words is "thirteen trillion, four billion, five hundred twenty million, two hundred twenty-two thousand".