Base | Representation |
---|---|
bin | 111100100011101010… |
… | …0011010101100111001 |
3 | 110102200002122121020012 |
4 | 1321013110122230321 |
5 | 4112313130202330 |
6 | 135424143311305 |
7 | 12252435652202 |
oct | 1710724325471 |
9 | 412602577205 |
10 | 130045553465 |
11 | 50174363123 |
12 | 21253bab535 |
13 | c356464049 |
14 | 64195665a9 |
15 | 35b1d60c95 |
hex | 1e4751ab39 |
130045553465 has 4 divisors (see below), whose sum is σ = 156054664164. Its totient is φ = 104036442768.
The previous prime is 130045553453. The next prime is 130045553483. The reversal of 130045553465 is 564355540031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 69769411321 + 60276142144 = 264139^2 + 245512^2 .
It is a cyclic number.
It is not a de Polignac number, because 130045553465 - 226 = 129978444601 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13004555342 + ... + 13004555351.
It is an arithmetic number, because the mean of its divisors is an integer number (39013666041).
Almost surely, 2130045553465 is an apocalyptic number.
It is an amenable number.
130045553465 is a deficient number, since it is larger than the sum of its proper divisors (26009110699).
130045553465 is an equidigital number, since it uses as much as digits as its factorization.
130045553465 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26009110698.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 130045553465 in words is "one hundred thirty billion, forty-five million, five hundred fifty-three thousand, four hundred sixty-five".
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