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130045553515 = 526009110703
BaseRepresentation
bin111100100011101010…
…0011010101101101011
3110102200002122121022001
41321013110122231223
54112313130203030
6135424143311431
712252435652303
oct1710724325553
9412602577261
10130045553515
1150174363169
1221253bab577
13c356464087
146419566603
1535b1d60cca
hex1e4751ab6b

130045553515 has 4 divisors (see below), whose sum is σ = 156054664224. Its totient is φ = 104036442808.

The previous prime is 130045553509. The next prime is 130045553543. The reversal of 130045553515 is 515355540031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130045553515 - 25 = 130045553483 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13004555347 + ... + 13004555356.

It is an arithmetic number, because the mean of its divisors is an integer number (39013666056).

Almost surely, 2130045553515 is an apocalyptic number.

130045553515 is a deficient number, since it is larger than the sum of its proper divisors (26009110709).

130045553515 is an equidigital number, since it uses as much as digits as its factorization.

130045553515 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26009110708.

The product of its (nonzero) digits is 112500, while the sum is 37.

The spelling of 130045553515 in words is "one hundred thirty billion, forty-five million, five hundred fifty-three thousand, five hundred fifteen".

Divisors: 1 5 26009110703 130045553515