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1300460446889 is a prime number
BaseRepresentation
bin10010111011001001011…
…110111010010010101001
311121022201022202120121122
4102323021132322102221
5132301320333300024
62433231232345025
7162645423261212
oct22731136722251
94538638676548
101300460446889
1146158202380a
121900556a5175
139582c611216
1446d2a7a6409
1523c64578d5e
hex12ec97ba4a9

1300460446889 has 2 divisors, whose sum is σ = 1300460446890. Its totient is φ = 1300460446888.

The previous prime is 1300460446871. The next prime is 1300460446891. The reversal of 1300460446889 is 9886440640031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1149398410000 + 151062036889 = 1072100^2 + 388667^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300460446889 - 220 = 1300459398313 is a prime.

Together with 1300460446891, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300460446889.

It is not a weakly prime, because it can be changed into another prime (1300460446189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650230223444 + 650230223445.

It is an arithmetic number, because the mean of its divisors is an integer number (650230223445).

Almost surely, 21300460446889 is an apocalyptic number.

It is an amenable number.

1300460446889 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300460446889 is an equidigital number, since it uses as much as digits as its factorization.

1300460446889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3981312, while the sum is 53.

The spelling of 1300460446889 in words is "one trillion, three hundred billion, four hundred sixty million, four hundred forty-six thousand, eight hundred eighty-nine".