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130050224155 = 526010044831
BaseRepresentation
bin111100100011110011…
…0001111000000011011
3110102200102102220012201
41321013212033000123
54112320324133110
6135424431351031
712252523444315
oct1710746170033
9412612386181
10130050224155
1150176a632a5
1221255682477
13c35740ac77
14641a0207b5
1535b2484b3a
hex1e4798f01b

130050224155 has 4 divisors (see below), whose sum is σ = 156060268992. Its totient is φ = 104040179320.

The previous prime is 130050224153. The next prime is 130050224159. The reversal of 130050224155 is 551422050031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 130050224155 - 21 = 130050224153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130050224153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13005022411 + ... + 13005022420.

It is an arithmetic number, because the mean of its divisors is an integer number (39015067248).

Almost surely, 2130050224155 is an apocalyptic number.

130050224155 is a deficient number, since it is larger than the sum of its proper divisors (26010044837).

130050224155 is an equidigital number, since it uses as much as digits as its factorization.

130050224155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26010044836.

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 130050224155 its reverse (551422050031), we get a palindrome (681472274186).

The spelling of 130050224155 in words is "one hundred thirty billion, fifty million, two hundred twenty-four thousand, one hundred fifty-five".

Divisors: 1 5 26010044831 130050224155