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13005055550531 = 111182277777321
BaseRepresentation
bin1011110100111111100110…
…1101110110010001000011
31201001021022200102002211202
42331033321231312101003
53201033323210104111
643354235014331415
72511404254151642
oct275177155662103
951037280362752
1013005055550531
11416445a8a9730
121560572959b6b
137344aa196935
1432d63b627359
15178458412b3b
hexbd3f9b76443

13005055550531 has 4 divisors (see below), whose sum is σ = 14187333327864. Its totient is φ = 11822777773200.

The previous prime is 13005055550503. The next prime is 13005055550551. The reversal of 13005055550531 is 13505555050031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13005055550531 - 214 = 13005055534147 is a prime.

It is a super-2 number, since 2×130050555505312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13005055550551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591138888650 + ... + 591138888671.

It is an arithmetic number, because the mean of its divisors is an integer number (3546833331966).

Almost surely, 213005055550531 is an apocalyptic number.

13005055550531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13005055550531 is a deficient number, since it is larger than the sum of its proper divisors (1182277777333).

13005055550531 is a wasteful number, since it uses less digits than its factorization.

13005055550531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1182277777332.

The product of its (nonzero) digits is 140625, while the sum is 38.

The spelling of 13005055550531 in words is "thirteen trillion, five billion, fifty-five million, five hundred fifty thousand, five hundred thirty-one".

Divisors: 1 11 1182277777321 13005055550531