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13005064903 is a prime number
BaseRepresentation
bin11000001110010100…
…11000101011000111
31020120100022202012111
430013022120223013
5203113244034103
65550251401451
7640164141055
oct140712305307
936510282174
1013005064903
115574024826
12262b453287
1312c345619c
148b52c71d5
15511b0286d
hex307298ac7

13005064903 has 2 divisors, whose sum is σ = 13005064904. Its totient is φ = 13005064902.

The previous prime is 13005064883. The next prime is 13005064921. The reversal of 13005064903 is 30946050031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13005064903 - 225 = 12971510471 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13005061903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502532451 + 6502532452.

It is an arithmetic number, because the mean of its divisors is an integer number (6502532452).

Almost surely, 213005064903 is an apocalyptic number.

13005064903 is a deficient number, since it is larger than the sum of its proper divisors (1).

13005064903 is an equidigital number, since it uses as much as digits as its factorization.

13005064903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 31.

The spelling of 13005064903 in words is "thirteen billion, five million, sixty-four thousand, nine hundred three".