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130052610543 = 3891217400237
BaseRepresentation
bin111100100011110111…
…1010101100111101111
3110102200120221010201110
41321013233111213233
54112321432014133
6135424554443103
712252552643602
oct1710757254757
9412616833643
10130052610543
1150178343219
1221256433493
13c357a6522b
14641a482339
1535b27a6c63
hex1e47bd59ef

130052610543 has 16 divisors (see below), whose sum is σ = 175496358240. Its totient is φ = 85656907776.

The previous prime is 130052610487. The next prime is 130052610547. The reversal of 130052610543 is 345016250031.

It is not a de Polignac number, because 130052610543 - 29 = 130052610031 is a prime.

It is a super-3 number, since 3×1300526105433 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130052610543.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130052610547) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 124821 + ... + 525057.

It is an arithmetic number, because the mean of its divisors is an integer number (10968522390).

Almost surely, 2130052610543 is an apocalyptic number.

130052610543 is a deficient number, since it is larger than the sum of its proper divisors (45443747697).

130052610543 is a wasteful number, since it uses less digits than its factorization.

130052610543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 401546.

The product of its (nonzero) digits is 10800, while the sum is 30.

Adding to 130052610543 its reverse (345016250031), we get a palindrome (475068860574).

The spelling of 130052610543 in words is "one hundred thirty billion, fifty-two million, six hundred ten thousand, five hundred forty-three".

Divisors: 1 3 89 267 1217 3651 108313 324939 400237 1200711 35621093 106863279 487088429 1461265287 43350870181 130052610543