Base | Representation |
---|---|
bin | 11101100100100001100101… |
… | …011000000101011010110000 |
3 | 122001110222022211012002010211 |
4 | 131210201211120011122300 |
5 | 114021243134444112334 |
6 | 1140333355511433504 |
7 | 36252020162605660 |
oct | 3544414530053260 |
9 | 561428284162124 |
10 | 130053310535344 |
11 | 384913323504a9 |
12 | 12705252685894 |
13 | 5774c89155661 |
14 | 241888444c1a0 |
15 | 1007eb98c2a64 |
hex | 7648656056b0 |
130053310535344 has 20 divisors (see below), whose sum is σ = 287975187614224. Its totient is φ = 55737133086528.
The previous prime is 130053310535243. The next prime is 130053310535359. The reversal of 130053310535344 is 443535013350031.
It is a junction number, because it is equal to n+sod(n) for n = 130053310535297 and 130053310535306.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 580595136207 + ... + 580595136430.
Almost surely, 2130053310535344 is an apocalyptic number.
130053310535344 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
130053310535344 is an abundant number, since it is smaller than the sum of its proper divisors (157921877078880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130053310535344 is a wasteful number, since it uses less digits than its factorization.
130053310535344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1161190272652 (or 1161190272646 counting only the distinct ones).
The product of its (nonzero) digits is 486000, while the sum is 40.
Adding to 130053310535344 its reverse (443535013350031), we get a palindrome (573588323885375).
The spelling of 130053310535344 in words is "one hundred thirty trillion, fifty-three billion, three hundred ten million, five hundred thirty-five thousand, three hundred forty-four".
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