Base | Representation |
---|---|
bin | 11000001110010111… |
… | …10000011000011000 |
3 | 1020120101000000000000 |
4 | 30013023300120120 |
5 | 203113342033102 |
6 | 5550303213000 |
7 | 640200165330 |
oct | 140713603030 |
9 | 36511000000 |
10 | 13005424152 |
11 | 557424a726 |
12 | 262b5a7160 |
13 | 12c3550866 |
14 | 8b537c0c0 |
15 | 511b7401c |
hex | 3072f0618 |
13005424152 has 416 divisors, whose sum is σ = 45916473600. Its totient is φ = 3367210176.
The previous prime is 13005424151. The next prime is 13005424153. The reversal of 13005424152 is 25142450031.
13005424152 is a `hidden beast` number, since 1 + 30 + 0 + 542 + 41 + 52 = 666.
It is an interprime number because it is at equal distance from previous prime (13005424151) and next prime (13005424153).
It is a hoax number, since the sum of its digits (27) coincides with the sum of the digits of its distinct prime factors.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13005424151) by changing a digit.
It is a polite number, since it can be written in 103 ways as a sum of consecutive naturals, for example, 565453213 + ... + 565453235.
Almost surely, 213005424152 is an apocalyptic number.
13005424152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13005424152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22958236800).
13005424152 is an abundant number, since it is smaller than the sum of its proper divisors (32911049448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13005424152 is an frugal number, since it uses more digits than its factorization.
13005424152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91 (or 54 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 27.
Adding to 13005424152 its reverse (25142450031), we get a palindrome (38147874183).
The spelling of 13005424152 in words is "thirteen billion, five million, four hundred twenty-four thousand, one hundred fifty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •