Base | Representation |
---|---|
bin | 111100100011111010… |
… | …1110010111010110001 |
3 | 110102200201010010220012 |
4 | 1321013311302322301 |
5 | 4112322400202114 |
6 | 135425055024305 |
7 | 12252603224222 |
oct | 1710765627261 |
9 | 412621103805 |
10 | 130054303409 |
11 | 5017929a088 |
12 | 21256b0b095 |
13 | c358208924 |
14 | 641a7a3249 |
15 | 35b29dd63e |
hex | 1e47d72eb1 |
130054303409 has 2 divisors, whose sum is σ = 130054303410. Its totient is φ = 130054303408.
The previous prime is 130054303399. The next prime is 130054303411. The reversal of 130054303409 is 904303450031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106845304384 + 23208999025 = 326872^2 + 152345^2 .
It is a cyclic number.
It is not a de Polignac number, because 130054303409 - 224 = 130037526193 is a prime.
Together with 130054303411, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (130054303439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65027151704 + 65027151705.
It is an arithmetic number, because the mean of its divisors is an integer number (65027151705).
Almost surely, 2130054303409 is an apocalyptic number.
It is an amenable number.
130054303409 is a deficient number, since it is larger than the sum of its proper divisors (1).
130054303409 is an equidigital number, since it uses as much as digits as its factorization.
130054303409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
The spelling of 130054303409 in words is "one hundred thirty billion, fifty-four million, three hundred three thousand, four hundred nine".
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