Base | Representation |
---|---|
bin | 11101100100100100000111… |
… | …001010100000100100011111 |
3 | 122001111020022222201100121101 |
4 | 131210210013022200210133 |
5 | 114021314214332314120 |
6 | 1140334525113413531 |
7 | 36252144352320250 |
oct | 3544440712404437 |
9 | 561436288640541 |
10 | 130056024885535 |
11 | 384924a5548a21 |
12 | 1270588b70a2a7 |
13 | 57752cc5c4a28 |
14 | 2418a60b38b27 |
15 | 10080c7d3e90a |
hex | 7649072a091f |
130056024885535 has 16 divisors (see below), whose sum is σ = 178362788668992. Its totient is φ = 89181154080000.
The previous prime is 130056024885487. The next prime is 130056024885569. The reversal of 130056024885535 is 535588420650031.
It is not a de Polignac number, because 130056024885535 - 213 = 130056024877343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29681685 + ... + 33780385.
It is an arithmetic number, because the mean of its divisors is an integer number (11147674291812).
Almost surely, 2130056024885535 is an apocalyptic number.
130056024885535 is a deficient number, since it is larger than the sum of its proper divisors (48306763783457).
130056024885535 is an equidigital number, since it uses as much as digits as its factorization.
130056024885535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5005314.
The product of its (nonzero) digits is 17280000, while the sum is 55.
The spelling of 130056024885535 in words is "one hundred thirty trillion, fifty-six billion, twenty-four million, eight hundred eighty-five thousand, five hundred thirty-five".
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