Base | Representation |
---|---|
bin | 11000001110011001… |
… | …00101010100111001 |
3 | 1020120101102000111001 |
4 | 30013030211110321 |
5 | 203113421003032 |
6 | 5550312005001 |
7 | 640202060515 |
oct | 140714452471 |
9 | 36511360431 |
10 | 13005641017 |
11 | 5574388656 |
12 | 262b690761 |
13 | 12c35c8495 |
14 | 8b53d7145 |
15 | 511bb83e7 |
hex | 307325539 |
13005641017 has 4 divisors (see below), whose sum is σ = 13425177856. Its totient is φ = 12586104180.
The previous prime is 13005640943. The next prime is 13005641021. The reversal of 13005641017 is 71014650031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 71014650031 = 13 ⋅5462665387.
It is a cyclic number.
It is not a de Polignac number, because 13005641017 - 223 = 12997252409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13005641317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209768373 + ... + 209768434.
It is an arithmetic number, because the mean of its divisors is an integer number (3356294464).
Almost surely, 213005641017 is an apocalyptic number.
It is an amenable number.
13005641017 is a deficient number, since it is larger than the sum of its proper divisors (419536839).
13005641017 is an equidigital number, since it uses as much as digits as its factorization.
13005641017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 419536838.
The product of its (nonzero) digits is 2520, while the sum is 28.
The spelling of 13005641017 in words is "thirteen billion, five million, six hundred forty-one thousand, seventeen".
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