Base | Representation |
---|---|
bin | 1011110101000010110010… |
… | …1110010101111101010001 |
3 | 1201001100112022200121121021 |
4 | 2331100230232111331101 |
5 | 3201042101244141403 |
6 | 43354455544355441 |
7 | 2511434415104602 |
oct | 275205456257521 |
9 | 51040468617537 |
10 | 13005911318353 |
11 | 416485996a768 |
12 | 1560771475b81 |
13 | 7345b5574325 |
14 | 32d6bd14bda9 |
15 | 1784a86038bd |
hex | bd42cb95f51 |
13005911318353 has 2 divisors, whose sum is σ = 13005911318354. Its totient is φ = 13005911318352.
The previous prime is 13005911318347. The next prime is 13005911318417. The reversal of 13005911318353 is 35381311950031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11719619632449 + 1286291685904 = 3423393^2 + 1134148^2 .
It is a cyclic number.
It is not a de Polignac number, because 13005911318353 - 25 = 13005911318321 is a prime.
It is not a weakly prime, because it can be changed into another prime (13005911316353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502955659176 + 6502955659177.
It is an arithmetic number, because the mean of its divisors is an integer number (6502955659177).
Almost surely, 213005911318353 is an apocalyptic number.
It is an amenable number.
13005911318353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13005911318353 is an equidigital number, since it uses as much as digits as its factorization.
13005911318353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800, while the sum is 43.
The spelling of 13005911318353 in words is "thirteen trillion, five billion, nine hundred eleven million, three hundred eighteen thousand, three hundred fifty-three".
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