Base | Representation |
---|---|
bin | 1011110101000010110010… |
… | …1110010101111110010001 |
3 | 1201001100112022200121200122 |
4 | 2331100230232111332101 |
5 | 3201042101244142132 |
6 | 43354455544400025 |
7 | 2511434415105023 |
oct | 275205456257621 |
9 | 51040468617618 |
10 | 13005911318417 |
11 | 416485996a816 |
12 | 1560771476015 |
13 | 7345b5574374 |
14 | 32d6bd14c013 |
15 | 1784a8603912 |
hex | bd42cb95f91 |
13005911318417 has 2 divisors, whose sum is σ = 13005911318418. Its totient is φ = 13005911318416.
The previous prime is 13005911318353. The next prime is 13005911318443. The reversal of 13005911318417 is 71481311950031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12310807272976 + 695104045441 = 3508676^2 + 833729^2 .
It is a cyclic number.
It is not a de Polignac number, because 13005911318417 - 26 = 13005911318353 is a prime.
It is not a weakly prime, because it can be changed into another prime (13005911318467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502955659208 + 6502955659209.
It is an arithmetic number, because the mean of its divisors is an integer number (6502955659209).
Almost surely, 213005911318417 is an apocalyptic number.
It is an amenable number.
13005911318417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13005911318417 is an equidigital number, since it uses as much as digits as its factorization.
13005911318417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 44.
The spelling of 13005911318417 in words is "thirteen trillion, five billion, nine hundred eleven million, three hundred eighteen thousand, four hundred seventeen".
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