Base | Representation |
---|---|
bin | 1011110101000011111111… |
… | …0111111111110110010111 |
3 | 1201001101100201021020120211 |
4 | 2331100333313333312113 |
5 | 3201043231022210333 |
6 | 43354551503110251 |
7 | 2511445366100461 |
oct | 275207767776627 |
9 | 51041321236524 |
10 | 13006232616343 |
11 | 4164a0427069a |
12 | 1560840ba2387 |
13 | 734636cbb295 |
14 | 32d70daa7131 |
15 | 1784c691cecd |
hex | bd43fdffd97 |
13006232616343 has 2 divisors, whose sum is σ = 13006232616344. Its totient is φ = 13006232616342.
The previous prime is 13006232616277. The next prime is 13006232616347. The reversal of 13006232616343 is 34361623260031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13006232616343 - 241 = 10807209360791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13006232616296 and 13006232616305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13006232616347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6503116308171 + 6503116308172.
It is an arithmetic number, because the mean of its divisors is an integer number (6503116308172).
Almost surely, 213006232616343 is an apocalyptic number.
13006232616343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13006232616343 is an equidigital number, since it uses as much as digits as its factorization.
13006232616343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 40.
Adding to 13006232616343 its reverse (34361623260031), we get a palindrome (47367855876374).
The spelling of 13006232616343 in words is "thirteen trillion, six billion, two hundred thirty-two million, six hundred sixteen thousand, three hundred forty-three".
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