13006270000037 has 4 divisors (see below), whose sum is σ = 13055723498400. Its totient is φ = 12956816501676.

The previous prime is 13006270000021. The next prime is 13006270000049. The reversal of 13006270000037 is 73000007260031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13006270000037 - 2⁴ = 13006270000021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13006269999964 and 13006270000009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13006270000837) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24726748787 + ... + 24726749312.

It is an arithmetic number, because the mean of its divisors is an integer number (3263930874600).

Almost surely, 2^{13006270000037} is an apocalyptic number.

It is an amenable number.

13006270000037 is a deficient number, since it is larger than the sum of its proper divisors (49453498363).

13006270000037 is an equidigital number, since it uses as much as digits as its factorization.

13006270000037 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49453498362.

The product of its (nonzero) digits is 5292, while the sum is 29.

Adding to 13006270000037 its reverse (73000007260031), we get a palindrome (86006277260068).

The spelling of 13006270000037 in words is "thirteen trillion, six billion, two hundred seventy million, thirty-seven", and thus it is an aban number.