Base | Representation |
---|---|
bin | 11000001110011110… |
… | …10001101110011001 |
3 | 1020120102201220010112 |
4 | 30013033101232121 |
5 | 203114111102121 |
6 | 5550335054105 |
7 | 640211061323 |
oct | 140717215631 |
9 | 36512656115 |
10 | 13006347161 |
11 | 5574820145 |
12 | 262b971335 |
13 | 12c37b4a12 |
14 | 8b553c613 |
15 | 511ca775b |
hex | 3073d1b99 |
13006347161 has 4 divisors (see below), whose sum is σ = 13006903092. Its totient is φ = 13005791232.
The previous prime is 13006347113. The next prime is 13006347223. The reversal of 13006347161 is 16174360031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 16174360031 = 17 ⋅951432943.
It can be written as a sum of positive squares in 2 ways, for example, as 12245635600 + 760711561 = 110660^2 + 27581^2 .
It is a cyclic number.
It is not a de Polignac number, because 13006347161 - 210 = 13006346137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13006347661) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241256 + ... + 290201.
It is an arithmetic number, because the mean of its divisors is an integer number (3251725773).
Almost surely, 213006347161 is an apocalyptic number.
It is an amenable number.
13006347161 is a deficient number, since it is larger than the sum of its proper divisors (555931).
13006347161 is an equidigital number, since it uses as much as digits as its factorization.
13006347161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 555930.
The product of its (nonzero) digits is 9072, while the sum is 32.
The spelling of 13006347161 in words is "thirteen billion, six million, three hundred forty-seven thousand, one hundred sixty-one".
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