13006773943 has 4 divisors (see below), whose sum is σ = 13426347328. Its totient is φ = 12587200560.

The previous prime is 13006773919. The next prime is 13006773973. The reversal of 13006773943 is 34937760031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34937760031 = 1609 ⋅21713959.

It is a cyclic number.

It is not a de Polignac number, because 13006773943 - 2⁵ = 13006773911 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13006773943.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13006773973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209786646 + ... + 209786707.

It is an arithmetic number, because the mean of its divisors is an integer number (3356586832).

Almost surely, 2^13006773943 is an apocalyptic number.

13006773943 is a deficient number, since it is larger than the sum of its proper divisors (419573385).

13006773943 is an equidigital number, since it uses as much as digits as its factorization.

13006773943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 419573384.

The product of its (nonzero) digits is 285768, while the sum is 43.

The spelling of 13006773943 in words is "thirteen billion, six million, seven hundred seventy-three thousand, nine hundred forty-three".