Search a number
-
+
130087687551 = 343362562517
BaseRepresentation
bin111100100100111010…
…1001001010101111111
3110102210000221020022220
41321021311021111333
54112404422000201
6135432250340423
712253460046123
oct1711165112577
9412700836286
10130087687551
1150196121088
122126612a713
13c3620c7063
146420db3583
1535b58d5036
hex1e49d4957f

130087687551 has 4 divisors (see below), whose sum is σ = 173450250072. Its totient is φ = 86725125032.

The previous prime is 130087687547. The next prime is 130087687601. The reversal of 130087687551 is 155786780031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130087687551 - 22 = 130087687547 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130087687494 and 130087687503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130087687511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21681281256 + ... + 21681281261.

It is an arithmetic number, because the mean of its divisors is an integer number (43362562518).

Almost surely, 2130087687551 is an apocalyptic number.

130087687551 is a deficient number, since it is larger than the sum of its proper divisors (43362562521).

130087687551 is an equidigital number, since it uses as much as digits as its factorization.

130087687551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43362562520.

The product of its (nonzero) digits is 1411200, while the sum is 51.

The spelling of 130087687551 in words is "one hundred thirty billion, eighty-seven million, six hundred eighty-seven thousand, five hundred fifty-one".

Divisors: 1 3 43362562517 130087687551