Base | Representation |
---|---|
bin | 1011110101010010000010… |
… | …1011110111100010111001 |
3 | 1201001202002120101010212221 |
4 | 2331110200223313202321 |
5 | 3201123442100411301 |
6 | 43400414035404041 |
7 | 2511641015004463 |
oct | 275244053674271 |
9 | 51052076333787 |
10 | 13010004310201 |
11 | 416656a299058 |
12 | 1561514153621 |
13 | 734ab85246b2 |
14 | 32d98a98b133 |
15 | 178647ae6da1 |
hex | bd520af78b9 |
13010004310201 has 2 divisors, whose sum is σ = 13010004310202. Its totient is φ = 13010004310200.
The previous prime is 13010004310187. The next prime is 13010004310231. The reversal of 13010004310201 is 10201340001031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6646594453801 + 6363409856400 = 2578099^2 + 2522580^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13010004310201 is a prime.
It is not a weakly prime, because it can be changed into another prime (13010004310231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505002155100 + 6505002155101.
It is an arithmetic number, because the mean of its divisors is an integer number (6505002155101).
Almost surely, 213010004310201 is an apocalyptic number.
It is an amenable number.
13010004310201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13010004310201 is an equidigital number, since it uses as much as digits as its factorization.
13010004310201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13010004310201 its reverse (10201340001031), we get a palindrome (23211344311232).
The spelling of 13010004310201 in words is "thirteen trillion, ten billion, four million, three hundred ten thousand, two hundred one".
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