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13010010433 = 72733637129
BaseRepresentation
bin11000001110111010…
…10000000101000001
31020120200122000012021
430013131100011001
5203121030313213
65550545401441
7640254156400
oct140735200501
936520560167
1013010010433
1155768a2442
122631039281
1312c4498234
148b5c13637
1551227cd8d
hex307750141

13010010433 has 12 divisors (see below), whose sum is σ = 15341414340. Its totient is φ = 10998675072.

The previous prime is 13010010413. The next prime is 13010010437. The reversal of 13010010433 is 33401001031.

It can be written as a sum of positive squares in 2 ways, for example, as 3135216049 + 9874794384 = 55993^2 + 99372^2 .

It is not a de Polignac number, because 13010010433 - 213 = 13010002241 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13010010437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1814988 + ... + 1822141.

It is an arithmetic number, because the mean of its divisors is an integer number (1278451195).

Almost surely, 213010010433 is an apocalyptic number.

It is an amenable number.

13010010433 is a deficient number, since it is larger than the sum of its proper divisors (2331403907).

13010010433 is an equidigital number, since it uses as much as digits as its factorization.

13010010433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3637216 (or 3637209 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13010010433 its reverse (33401001031), we get a palindrome (46411011464).

The spelling of 13010010433 in words is "thirteen billion, ten million, ten thousand, four hundred thirty-three".

Divisors: 1 7 49 73 511 3577 3637129 25459903 178219321 265510417 1858572919 13010010433