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13010011111103 = 59143121997513
BaseRepresentation
bin1011110101010010000100…
…0101110011111010111111
31201001202010001011122222012
42331110201011303322333
53201124000321023403
643400414441241435
72511641126551256
oct275244105637277
951052101148865
1013010011111103
114166573113736
12156151649327b
13734ab9a660b6
1432d98b83b79d
151786484dbed8
hexbd521173ebf

13010011111103 has 4 divisors (see below), whose sum is σ = 13010033700048. Its totient is φ = 13009988522160.

The previous prime is 13010011111091. The next prime is 13010011111193. The reversal of 13010011111103 is 30111111001031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13010011111103 - 216 = 13010011045567 is a prime.

It is a super-2 number, since 2×130100111111032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13010011111193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10407326 + ... + 11590187.

It is an arithmetic number, because the mean of its divisors is an integer number (3252508425012).

Almost surely, 213010011111103 is an apocalyptic number.

13010011111103 is a deficient number, since it is larger than the sum of its proper divisors (22588945).

13010011111103 is an equidigital number, since it uses as much as digits as its factorization.

13010011111103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22588944.

The product of its (nonzero) digits is 9, while the sum is 14.

Adding to 13010011111103 its reverse (30111111001031), we get a palindrome (43121122112134).

The spelling of 13010011111103 in words is "thirteen trillion, ten billion, eleven million, one hundred eleven thousand, one hundred three".

Divisors: 1 591431 21997513 13010011111103