Base | Representation |
---|---|
bin | 10010111011101001101… |
… | …101110101011100100001 |
3 | 11121101010000100012201221 |
4 | 102323221231311130201 |
5 | 132303422303330423 |
6 | 2433401031255041 |
7 | 162665010664534 |
oct | 22735155653441 |
9 | 4541100305657 |
10 | 1301001230113 |
11 | 46182a3061a2 |
12 | 19018681a481 |
13 | 958b76754b0 |
14 | 46d7c536a1b |
15 | 23c96c9ae5d |
hex | 12ee9b75721 |
1301001230113 has 32 divisors (see below), whose sum is σ = 1452433006080. Its totient is φ = 1157716934400.
The previous prime is 1301001230101. The next prime is 1301001230117. The reversal of 1301001230113 is 3110321001031.
It is not a de Polignac number, because 1301001230113 - 225 = 1300967675681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1301001230117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95563695 + ... + 95577307.
It is an arithmetic number, because the mean of its divisors is an integer number (45388531440).
Almost surely, 21301001230113 is an apocalyptic number.
1301001230113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1301001230113 is a deficient number, since it is larger than the sum of its proper divisors (151431775967).
1301001230113 is a wasteful number, since it uses less digits than its factorization.
1301001230113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16089.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1301001230113 its reverse (3110321001031), we get a palindrome (4411322231144).
The spelling of 1301001230113 in words is "one trillion, three hundred one billion, one million, two hundred thirty thousand, one hundred thirteen".
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