Base | Representation |
---|---|
bin | 111100100101010010… |
… | …1011000001001011111 |
3 | 110102210220201121000121 |
4 | 1321022211120021133 |
5 | 4112421141043403 |
6 | 135433421335411 |
7 | 12254002365601 |
oct | 1711245301137 |
9 | 412726647017 |
10 | 130100331103 |
11 | 501a22773a6 |
12 | 2126a407567 |
13 | c364902c52 |
14 | 6422945171 |
15 | 35b6a813bd |
hex | 1e4a95825f |
130100331103 has 2 divisors, whose sum is σ = 130100331104. Its totient is φ = 130100331102.
The previous prime is 130100331091. The next prime is 130100331113. The reversal of 130100331103 is 301133001031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130100331103 is a prime.
It is a super-2 number, since 2×1301003311032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130100331113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65050165551 + 65050165552.
It is an arithmetic number, because the mean of its divisors is an integer number (65050165552).
Almost surely, 2130100331103 is an apocalyptic number.
130100331103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130100331103 is an equidigital number, since it uses as much as digits as its factorization.
130100331103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 130100331103 its reverse (301133001031), we get a palindrome (431233332134).
The spelling of 130100331103 in words is "one hundred thirty billion, one hundred million, three hundred thirty-one thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •