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1301014202143 = 1487874925489
BaseRepresentation
bin10010111011101010011…
…111010100011100011111
311121101010220202021000111
4102323222133110130133
5132303434113432033
62433402213310451
7162665226153055
oct22735237243437
94541126667014
101301014202143
11461836666287
1219018b035427
13958ba267a56
1446d801521d5
1523c97eae7cd
hex12eea7d471f

1301014202143 has 4 divisors (see below), whose sum is σ = 1301889129120. Its totient is φ = 1300139275168.

The previous prime is 1301014202093. The next prime is 1301014202153. The reversal of 1301014202143 is 3412024101031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301014202143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301014202153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437461258 + ... + 437464231.

It is an arithmetic number, because the mean of its divisors is an integer number (325472282280).

Almost surely, 21301014202143 is an apocalyptic number.

1301014202143 is a deficient number, since it is larger than the sum of its proper divisors (874926977).

1301014202143 is an equidigital number, since it uses as much as digits as its factorization.

1301014202143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 874926976.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1301014202143 its reverse (3412024101031), we get a palindrome (4713038303174).

The spelling of 1301014202143 in words is "one trillion, three hundred one billion, fourteen million, two hundred two thousand, one hundred forty-three".

Divisors: 1 1487 874925489 1301014202143