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13010203334341 is a prime number
BaseRepresentation
bin1011110101010010110010…
…0011000101011011000101
31201001202121102212121200101
42331110230203011123011
53201124344023144331
643400445505244101
72511645652456003
oct275245443053305
951052542777611
1013010203334341
114166661674914
12156156a933631
13734b1a829765
1432d9a9197a73
1517865a30c061
hexbd52c8c56c5

13010203334341 has 2 divisors, whose sum is σ = 13010203334342. Its totient is φ = 13010203334340.

The previous prime is 13010203334287. The next prime is 13010203334357. The reversal of 13010203334341 is 14343330201031.

13010203334341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12319018943716 + 691184390625 = 3509846^2 + 831375^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010203334341 - 219 = 13010202810053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13010203334941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505101667170 + 6505101667171.

It is an arithmetic number, because the mean of its divisors is an integer number (6505101667171).

Almost surely, 213010203334341 is an apocalyptic number.

It is an amenable number.

13010203334341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010203334341 is an equidigital number, since it uses as much as digits as its factorization.

13010203334341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 13010203334341 its reverse (14343330201031), we get a palindrome (27353533535372).

The spelling of 13010203334341 in words is "thirteen trillion, ten billion, two hundred three million, three hundred thirty-four thousand, three hundred forty-one".