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130102100103 = 3421110298591
BaseRepresentation
bin111100100101010110…
…0001000000010000111
3110102211001001110122010
41321022230020002013
54112422114200403
6135433523305303
712254023414203
oct1711254100207
9412731043563
10130102100103
11501a3275488
122126ab1b233
13c3650a21b1
146422c85b03
1535b6cd0603
hex1e4ab08087

130102100103 has 8 divisors (see below), whose sum is σ = 173510678016. Its totient is φ = 86714127800.

The previous prime is 130102100071. The next prime is 130102100131. The reversal of 130102100103 is 301001201031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130102100103 - 25 = 130102100071 is a prime.

It is a super-2 number, since 2×1301021001032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130102100203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5136663 + ... + 5161928.

It is an arithmetic number, because the mean of its divisors is an integer number (21688834752).

Almost surely, 2130102100103 is an apocalyptic number.

130102100103 is a deficient number, since it is larger than the sum of its proper divisors (43408577913).

130102100103 is a wasteful number, since it uses less digits than its factorization.

130102100103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10302805.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 130102100103 its reverse (301001201031), we get a palindrome (431103301134).

The spelling of 130102100103 in words is "one hundred thirty billion, one hundred two million, one hundred thousand, one hundred three".

Divisors: 1 3 4211 12633 10298591 30895773 43367366701 130102100103