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130102220121103 = 733177492796891
BaseRepresentation
bin11101100101001111001000…
…100111010110010000001111
3122001122122120102012110122001
4131211033020213112100033
5114023043321322333403
61140412045041533131
736255401204331316
oct3545171047262017
9561578512173561
10130102220121103
113850005055615a
12127128223441a7
13577978201c849
14241ada401727d
1510093cd676c1d
hex7653c89d640f

130102220121103 has 4 divisors (see below), whose sum is σ = 130279712918728. Its totient is φ = 129924727323480.

The previous prime is 130102220121043. The next prime is 130102220121109. The reversal of 130102220121103 is 301121022201031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130102220121103 - 213 = 130102220112911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130102220121109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88746397713 + ... + 88746399178.

It is an arithmetic number, because the mean of its divisors is an integer number (32569928229682).

Almost surely, 2130102220121103 is an apocalyptic number.

130102220121103 is a deficient number, since it is larger than the sum of its proper divisors (177492797625).

130102220121103 is an equidigital number, since it uses as much as digits as its factorization.

130102220121103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177492797624.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 130102220121103 its reverse (301121022201031), we get a palindrome (431223242322134).

The spelling of 130102220121103 in words is "one hundred thirty trillion, one hundred two billion, two hundred twenty million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 733 177492796891 130102220121103