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1301023111312 = 2481313944457
BaseRepresentation
bin10010111011101011000…
…001010011100010010000
311121101011112111220002201
4102323223001103202100
5132303443404030222
62433403132252544
7162665364660241
oct22735301234220
94541145456081
101301023111312
114618406a0931
12190192011154
13958bc066c52
1446d813d0cc8
1523c98b6e427
hex12eeb053890

1301023111312 has 10 divisors (see below), whose sum is σ = 2520732278198. Its totient is φ = 650511555648.

The previous prime is 1301023111307. The next prime is 1301023111321. The reversal of 1301023111312 is 2131113201031.

It can be written as a sum of positive squares in only one way, i.e., 1301023109376 + 1936 = 1140624^2 + 44^2 .

It is a super-2 number, since 2×13010231113122 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1301023111312.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40656972213 + ... + 40656972244.

Almost surely, 21301023111312 is an apocalyptic number.

It is an amenable number.

1301023111312 is a deficient number, since it is larger than the sum of its proper divisors (1219709166886).

1301023111312 is an equidigital number, since it uses as much as digits as its factorization.

1301023111312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81313944465 (or 81313944459 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1301023111312 its reverse (2131113201031), we get a palindrome (3432136312343).

The spelling of 1301023111312 in words is "one trillion, three hundred one billion, twenty-three million, one hundred eleven thousand, three hundred twelve".

Divisors: 1 2 4 8 16 81313944457 162627888914 325255777828 650511555656 1301023111312