1301023212301 has 4 divisors (see below), whose sum is σ = 1301034046432. Its totient is φ = 1301012378172.

The previous prime is 1301023212299. The next prime is 1301023212319. The reversal of 1301023212301 is 1032123201031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301023212301 - 2¹ = 1301023212299 is a prime.

It is a super-2 number, since 2×1301023212301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301023212331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5234895 + ... + 5477788.

It is an arithmetic number, because the mean of its divisors is an integer number (325258511608).

Almost surely, 2^{1301023212301} is an apocalyptic number.

It is an amenable number.

1301023212301 is a deficient number, since it is larger than the sum of its proper divisors (10834131).

1301023212301 is a wasteful number, since it uses less digits than its factorization.

1301023212301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10834130.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1301023212301 its reverse (1032123201031), we get a palindrome (2333146413332).

The spelling of 1301023212301 in words is "one trillion, three hundred one billion, twenty-three million, two hundred twelve thousand, three hundred one".