Base | Representation |
---|---|
bin | 11101100101001111001111… |
… | …001010111101101110010111 |
3 | 122001122122212002012001021102 |
4 | 131211033033022331232113 |
5 | 114023044033002333421 |
6 | 1140412104011340315 |
7 | 36255404011323125 |
oct | 3545171712755627 |
9 | 561578762161242 |
10 | 130102330121111 |
11 | 385000a7657857 |
12 | 1271285315169b |
13 | 577979ba54bca |
14 | 241adb488c915 |
15 | 10093d815460b |
hex | 7653cf2bdb97 |
130102330121111 has 4 divisors (see below), whose sum is σ = 130102622525400. Its totient is φ = 130102037716824.
The previous prime is 130102330121107. The next prime is 130102330121117. The reversal of 130102330121111 is 111121033201031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130102330121111 - 22 = 130102330121107 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130102330121117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145533716 + ... + 146424953.
It is an arithmetic number, because the mean of its divisors is an integer number (32525655631350).
Almost surely, 2130102330121111 is an apocalyptic number.
130102330121111 is a deficient number, since it is larger than the sum of its proper divisors (292404289).
130102330121111 is an equidigital number, since it uses as much as digits as its factorization.
130102330121111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 292404288.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 130102330121111 its reverse (111121033201031), we get a palindrome (241223363322142).
The spelling of 130102330121111 in words is "one hundred thirty trillion, one hundred two billion, three hundred thirty million, one hundred twenty-one thousand, one hundred eleven".
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