Base | Representation |
---|---|
bin | 11101100101001111111101… |
… | …101010011110000100100001 |
3 | 122001122201212102220201001122 |
4 | 131211033331222132010201 |
5 | 114023102132143211001 |
6 | 1140412313233542025 |
7 | 36255432232314266 |
oct | 3545177552360441 |
9 | 561581772821048 |
10 | 130103110132001 |
11 | 38500467985556 |
12 | 12712a30414915 |
13 | 5779894529606 |
14 | 241b04a2d326d |
15 | 100943187db1b |
hex | 7653fda9e121 |
130103110132001 has 2 divisors, whose sum is σ = 130103110132002. Its totient is φ = 130103110132000.
The previous prime is 130103110131979. The next prime is 130103110132033. The reversal of 130103110132001 is 100231011301031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116355032666401 + 13748077465600 = 10786799^2 + 3707840^2 .
It is a cyclic number.
It is not a de Polignac number, because 130103110132001 - 210 = 130103110130977 is a prime.
It is not a weakly prime, because it can be changed into another prime (130103110135001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051555066000 + 65051555066001.
It is an arithmetic number, because the mean of its divisors is an integer number (65051555066001).
Almost surely, 2130103110132001 is an apocalyptic number.
It is an amenable number.
130103110132001 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103110132001 is an equidigital number, since it uses as much as digits as its factorization.
130103110132001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 130103110132001 its reverse (100231011301031), we get a palindrome (230334121433032).
The spelling of 130103110132001 in words is "one hundred thirty trillion, one hundred three billion, one hundred ten million, one hundred thirty-two thousand, one".
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