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13010311951657 is a prime number
BaseRepresentation
bin1011110101010011001100…
…0001011011010100101001
31201001202220000020221121221
42331110303001123110221
53201130104324423112
643400504345302041
72511651441631366
oct275246301332451
951052800227557
1013010311951657
114166707a11699
12156159b194921
13734b37199667
1432d9b978d46d
15178664b14e07
hexbd53305b529

13010311951657 has 2 divisors, whose sum is σ = 13010311951658. Its totient is φ = 13010311951656.

The previous prime is 13010311951649. The next prime is 13010311951757. The reversal of 13010311951657 is 75615911301031.

It is a happy number.

13010311951657 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8038789996176 + 4971521955481 = 2835276^2 + 2229691^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010311951657 - 23 = 13010311951649 is a prime.

It is not a weakly prime, because it can be changed into another prime (13010311951607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505155975828 + 6505155975829.

It is an arithmetic number, because the mean of its divisors is an integer number (6505155975829).

Almost surely, 213010311951657 is an apocalyptic number.

It is an amenable number.

13010311951657 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010311951657 is an equidigital number, since it uses as much as digits as its factorization.

13010311951657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 85050, while the sum is 43.

The spelling of 13010311951657 in words is "thirteen trillion, ten billion, three hundred eleven million, nine hundred fifty-one thousand, six hundred fifty-seven".