Base | Representation |
---|---|
bin | 111100100101011000… |
… | …0110010001110111011 |
3 | 110102211010100112010012 |
4 | 1321022300302032323 |
5 | 4112422422242111 |
6 | 135434005412135 |
7 | 12254036662211 |
oct | 1711260621673 |
9 | 412733315105 |
10 | 130103321531 |
11 | 501a3a2a127 |
12 | 2126b40a04b |
13 | c36540c131 |
14 | 64230c2cb1 |
15 | 35b6e7248b |
hex | 1e4ac323bb |
130103321531 has 2 divisors, whose sum is σ = 130103321532. Its totient is φ = 130103321530.
The previous prime is 130103321507. The next prime is 130103321549. The reversal of 130103321531 is 135123301031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130103321531 - 234 = 112923452347 is a prime.
It is a super-2 number, since 2×1301033215312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130103321497 and 130103321506.
It is not a weakly prime, because it can be changed into another prime (130103321431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051660765 + 65051660766.
It is an arithmetic number, because the mean of its divisors is an integer number (65051660766).
Almost surely, 2130103321531 is an apocalyptic number.
130103321531 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103321531 is an equidigital number, since it uses as much as digits as its factorization.
130103321531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 130103321531 its reverse (135123301031), we get a palindrome (265226622562).
The spelling of 130103321531 in words is "one hundred thirty billion, one hundred three million, three hundred twenty-one thousand, five hundred thirty-one".
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