Base | Representation |
---|---|
bin | 11000001110111100… |
… | …11110110111001011 |
3 | 1020120201020101212001 |
4 | 30013132132313023 |
5 | 203121121130011 |
6 | 5551000331431 |
7 | 640260002245 |
oct | 140736366713 |
9 | 36521211761 |
10 | 13010333131 |
11 | 5576aa2934 |
12 | 2631173b77 |
13 | 12c457c093 |
14 | 8b5c99095 |
15 | 5122e37c1 |
hex | 30779edcb |
13010333131 has 2 divisors, whose sum is σ = 13010333132. Its totient is φ = 13010333130.
The previous prime is 13010333117. The next prime is 13010333143. The reversal of 13010333131 is 13133301031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13010333131 - 221 = 13008235979 is a prime.
It is a super-2 number, since 2×130103331312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13010333099 and 13010333108.
It is not a weakly prime, because it can be changed into another prime (13010333101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505166565 + 6505166566.
It is an arithmetic number, because the mean of its divisors is an integer number (6505166566).
Almost surely, 213010333131 is an apocalyptic number.
13010333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13010333131 is an equidigital number, since it uses as much as digits as its factorization.
13010333131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 13010333131 its reverse (13133301031), we get a palindrome (26143634162).
It can be divided in two parts, 1301033 and 3131, that added together give a square (1304164 = 11422).
The spelling of 13010333131 in words is "thirteen billion, ten million, three hundred thirty-three thousand, one hundred thirty-one".
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