Base | Representation |
---|---|
bin | 11101100101010000011011… |
… | …111001000100100111110011 |
3 | 122001122210011210012022101122 |
4 | 131211100123321010213303 |
5 | 114023104202010321103 |
6 | 1140412435431452455 |
7 | 36255450631055351 |
oct | 3545203371044763 |
9 | 561583153168348 |
10 | 130103617276403 |
11 | 385006a8181661 |
12 | 12712b5222712b |
13 | 5779945613564 |
14 | 241b0977c87d1 |
15 | 1009461158b38 |
hex | 76541be449f3 |
130103617276403 has 2 divisors, whose sum is σ = 130103617276404. Its totient is φ = 130103617276402.
The previous prime is 130103617276393. The next prime is 130103617276433. The reversal of 130103617276403 is 304672716301031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130103617276403 is a prime.
It is a super-3 number, since 3×1301036172764033 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (130103617276433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051808638201 + 65051808638202.
It is an arithmetic number, because the mean of its divisors is an integer number (65051808638202).
Almost surely, 2130103617276403 is an apocalyptic number.
130103617276403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103617276403 is an equidigital number, since it uses as much as digits as its factorization.
130103617276403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 381024, while the sum is 44.
The spelling of 130103617276403 in words is "one hundred thirty trillion, one hundred three billion, six hundred seventeen million, two hundred seventy-six thousand, four hundred three".
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