Base | Representation |
---|---|
bin | 11101100101010000011011… |
… | …111001000100101000010001 |
3 | 122001122210011210012022102202 |
4 | 131211100123321010220101 |
5 | 114023104202010321213 |
6 | 1140412435431452545 |
7 | 36255450631055423 |
oct | 3545203371045021 |
9 | 561583153168382 |
10 | 130103617276433 |
11 | 385006a8181689 |
12 | 12712b52227155 |
13 | 5779945613588 |
14 | 241b0977c8813 |
15 | 1009461158b58 |
hex | 76541be44a11 |
130103617276433 has 2 divisors, whose sum is σ = 130103617276434. Its totient is φ = 130103617276432.
The previous prime is 130103617276403. The next prime is 130103617276441. The reversal of 130103617276433 is 334672716301031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87804827198929 + 42298790077504 = 9370423^2 + 6503752^2 .
It is a cyclic number.
It is not a de Polignac number, because 130103617276433 - 220 = 130103616227857 is a prime.
It is not a weakly prime, because it can be changed into another prime (130103617276403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051808638216 + 65051808638217.
It is an arithmetic number, because the mean of its divisors is an integer number (65051808638217).
Almost surely, 2130103617276433 is an apocalyptic number.
It is an amenable number.
130103617276433 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103617276433 is an equidigital number, since it uses as much as digits as its factorization.
130103617276433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1143072, while the sum is 47.
The spelling of 130103617276433 in words is "one hundred thirty trillion, one hundred three billion, six hundred seventeen million, two hundred seventy-six thousand, four hundred thirty-three".
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