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130104254353 = 2323813237547
BaseRepresentation
bin111100100101011010…
…0010101111110010001
3110102211012002220201011
41321022310111332101
54112423142114403
6135434041410521
712254050625623
oct1711264257621
9412735086634
10130104254353
11501a4506a57
122126b799a41
13c3656778b8
146423286c13
1535b70a8a6d
hex1e4ad15f91

130104254353 has 8 divisors (see below), whose sum is σ = 135767233728. Its totient is φ = 124441797744.

The previous prime is 130104254323. The next prime is 130104254383. The reversal of 130104254353 is 353452401031.

It is an interprime number because it is at equal distance from previous prime (130104254323) and next prime (130104254383).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130104254353 - 25 = 130104254321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130104254323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 428926 + ... + 666472.

It is an arithmetic number, because the mean of its divisors is an integer number (16970904216).

Almost surely, 2130104254353 is an apocalyptic number.

It is an amenable number.

130104254353 is a deficient number, since it is larger than the sum of its proper divisors (5662979375).

130104254353 is a wasteful number, since it uses less digits than its factorization.

130104254353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 261383.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 130104254353 its reverse (353452401031), we get a palindrome (483556655384).

The spelling of 130104254353 in words is "one hundred thirty billion, one hundred four million, two hundred fifty-four thousand, three hundred fifty-three".

Divisors: 1 23 23813 237547 547699 5463581 5656706711 130104254353